Flatten Nested List Iterator
Problem:
Analysis:
3/16/2018 update:
Remember to call hasNext() in next() to make sure no error.
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Use stack to flat the nested list. Push items to stack in reverse order. When determine hasNext, if the stack top is not Integer, then flat it.
Solution:
Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:
Given the list
Given the list
[[1,1],2,[1,1]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be:
[1,1,2,1,1]
.
Example 2:
Given the list
Given the list
[1,[4,[6]]]
,
By calling next repeatedly until hasNext returns false, the order of elements returned by next should be:
[1,4,6]
.Analysis:
3/16/2018 update:
Remember to call hasNext() in next() to make sure no error.
public class NestedIterator implements Iterator<Integer> { Stack<NestedInteger> stack = new Stack<>(); public NestedIterator(List<NestedInteger> nestedList) { pushToStack(nestedList); } @Override public Integer next() { return hasNext() ? stack.pop().getInteger() : null; } @Override public boolean hasNext() { while (!stack.isEmpty()) { NestedInteger cur = stack.peek(); if (cur.isInteger()) { return true; } stack.pop(); pushToStack(cur.getList()); } return false; } private void pushToStack(List<NestedInteger> list) { for (int i = list.size() - 1; i >= 0; i--) { stack.push(list.get(i)); } } }
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Use stack to flat the nested list. Push items to stack in reverse order. When determine hasNext, if the stack top is not Integer, then flat it.
Solution:
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer,
* // rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds,
* // if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds,
* // if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
import java.util.Iterator;
public class NestedIterator implements Iterator<Integer> {
private Stack<NestedInteger> stack;
public NestedIterator(List<NestedInteger> nestedList) {
// Initialize your data structure here.
stack = new Stack<>();
updateStack(nestedList);
}
private void updateStack(List<NestedInteger> nestedList) {
Stack<NestedInteger> temp = new Stack<>();
for (NestedInteger n: nestedList) {
temp.push(n);
}
while (!temp.isEmpty()) {
stack.push(temp.pop());
}
}
// @return {int} the next element in the iteration
@Override
public Integer next() {
// Write your code here
if(!hasNext()) {
return null;
}
return stack.pop().getInteger();
}
// @return {boolean} true if the iteration has more element or false
@Override
public boolean hasNext() {
// Write your code here
// get next
while (!stack.isEmpty() && !stack.peek().isInteger()) {
updateStack(stack.pop().getList());
}
return !stack.isEmpty();
}
@Override
public void remove() {}
}
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v.add(i.next());
*/
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