150. Evaluate Reverse Polish Notation
Problem:
Analysis:
It's every easy with stack, but need to pay attention of the order of stack pops when doing divide.
Solution:
Evaluate the value of an arithmetic expression in Reverse Polish Notation.
Valid operators are
+
, -
, *
, /
. Each operand may be an integer or another expression.
Note:
- Division between two integers should truncate toward zero.
- The given RPN expression is always valid. That means the expression would always evaluate to a result and there won't be any divide by zero operation.
Example 1:
Input: ["2", "1", "+", "3", "*"] Output: 9 Explanation: ((2 + 1) * 3) = 9
Example 2:
Input: ["4", "13", "5", "/", "+"] Output: 6 Explanation: (4 + (13 / 5)) = 6
It's every easy with stack, but need to pay attention of the order of stack pops when doing divide.
Solution:
class Solution { public int evalRPN(String[] tokens) { Stack<Integer> stack = new Stack<>(); for (String s: tokens) { switch (s) { case "+": stack.push(stack.pop() + stack.pop()); break; case "-": stack.push(-stack.pop() + stack.pop()); break; case "*": stack.push(stack.pop() * stack.pop()); break; case "/": int n2 = stack.pop(), n1 = stack.pop(); stack.push(n1 / n2); break; default: stack.push(Integer.valueOf(s)); break; } } return stack.peek(); } }
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