397. Integer Replacement
Problem:
User recursion. Not fit for dp, because if n is odd, n can add 1.
Solution:
n + 1 might overflow, use long in recursion instead of int.
Given a positive integer n and you can do operations as follow:
- If n is even, replace n with
n/2
. - If n is odd, you can replace n with either
n + 1
orn - 1
.
What is the minimum number of replacements needed for n to become 1?
Example 1:
Input: 8 Output: 3 Explanation: 8 -> 4 -> 2 -> 1
Example 2:
Input: 7 Output: 4 Explanation: 7 -> 8 -> 4 -> 2 -> 1 or 7 -> 6 -> 3 -> 2 -> 1Analysis:
User recursion. Not fit for dp, because if n is odd, n can add 1.
Solution:
n + 1 might overflow, use long in recursion instead of int.
class Solution { public int integerReplacement(int n) { return (int)longReplacement(n); } private int longReplacement(long n) { if (n == 1) return 0; if (n % 2 == 0) return longReplacement(n/2) + 1; else return Math.min(longReplacement(n + 1), longReplacement(n - 1)) + 1; } }
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