165. Compare Version Numbers

Problem:

Compare two version numbers version1 and version2.
If version1 > version2 return 1; if version1 < version2 return -1;otherwise return 0.

You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

Example 1:

Input: version1 = "0.1", version2 = "1.1"
Output: -1

Example 2:

Input: version1 = "1.0.1", version2 = "1"
Output: 1

Example 3:

Input: version1 = "7.5.2.4", version2 = "7.5.3"
Output: -1

Analysis:

这道题实现的时候要注意在数组越界的时候把值赋为零。

Solution:

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class Solution { public int compareVersion(String version1, String version2) { String[] v1 = version1.split("\\."); String[] v2 = version2.split("\\."); int len1 = v1.length, len2 = v2.length; for (int i = 0; i < Math.max(len1, len2); i++) { int value1 = (i < len1) ? Integer.valueOf(v1[i]) : 0; int value2 = (i < len2) ? Integer.valueOf(v2[i]) : 0; if (value1 > value2) return 1; else if (value1 < value2) return -1; } return 0; } }